Sandeep Garg (2019) - GeniusJnr

Sandeep Garg (2019) : MCQ, free quiz, mock quiz, practise questions, olympiad preparation

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Sandeep Garg (2019)
Chapters
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Organisation of Data
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Tabular Presentation
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Diagrammatic Presentation
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Graphic Presentation
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Measures of Central Tendency- Arithmetic Mean
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Measures of Central Tendency- Median and Mode
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Questions
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Following are the figures of marks obtained by 40 students. You ae required to arrange them in ascending and in descending order.
15 18 16 14 10 6 5 3 8 7
22 18 14 19 17 8 6 4 10 3
12 16 15 13 11 10 18 22 14 19
11 18 22 14 25 21 17 8 9 10
solve  
Heights (in inches) of 35 students of a class in given below. Classify the following data in a discrete frequency series
58 60 72 68 58 55 58 72 55 68 66 60
60 55 76 66 58 72 68 60 55 68 55 58
62 66 72 58 60 68 55 58 65 72 68  
solve  
The following are the marks of the 30 students in statistics. prepare a frequency distribution taking the class−intervals as 10−20, 20−30 and so on.
12 33 23 25 18 35 37 49 54 51 37 15 33 42 45
47 55 69 65 63 46 29 18 37 46 59 29 35 45 27
solve  
Following are the marks (out of 100) obtained by 50 students in statistics:
70 55 51 42 57 45 60 47 63 53
33 65 39 82 55 64 58 61 65 42
50 52 53 45 45 25 36 59 63 39
65 54 49 54 64 75 42 41 52 35
30 35 15 48 26 20 40 55 46 18
make a frequency distribution taking the first class interval as 0-10.
solve  
Prepare a frequency table taking class intervals 20−24, 25−29, 30−34 and so on, from the following data:
21 20 55 39 48 46 36 54 42 30
29 42 32 40 34 31 35 37 52 44
39 45 37 33 51 53 52 46 43 47
41 26 52 48 25 34 37 33 36 27
54 36 41 33 23 39 28 44 45 38
solve  
From the following data, calculate the lower limit of the first class and upper limit of the last class.
Daily Wages Less than 120 120−140 140−160 160−180 Above 180
No. of Workers 35 12 10 40 13
solve  
Calculate the missing class-intervals from the following distribution:
Class-Interval Below 20 20−50 50−90 90−140 More than 140
Frequency 7 12 16 2 4
solve  
Convert the following 'more than' cumulative frequency distribution into a 'less than' cumulative frequency distribution
Class-Interval (More than) 10 20 30 40 50 60 70 80
Frequency 124 119 107 84 55 31 12 2
solve  
Convert the following cumulative frequency series into simple frequency series
Marks No. of Students
Less than 20 10
Less than 40 18
Less than 60 25
Less than 80 45
Less than 100 55
solve  

Prepare a frequency distribution from the following data:

Mid-Points 25 35 45 55 65 75
Frequency 6 10 9 12 8 5
solve  
The ages of 20 husbands and wives are given below. Form a two-way frequency table showing the relationship between the ages of husbands and wives with the class-intervals 20−25, 25−30, etc.
S.No Age of Husband Age of Wife S. No. Age of Husband Age of Wife
1 28 23 11 27 24
2 37 30 12 39 34
3 42 40 13 23 20
4 25 26 14 33 31
5 29 25 15 36 29
6 47 31 16 32 35
7 37 35 17 22 23
8 35 25 18 29 27
9 23 21 19 38 34
10 41 38 20 48 47
solve  
The following data give the points scored in a tennis match by two player X and Y at the end of twenty games:
(10,12) (2,11) (7,9) (15,19) (17,21) (12,8) (16,10) (14,14) (22,18) (16,4)
(15,16) (22,20) (19,15) (7,18) (11,11) (12,18) (10,10) (5,13) (11,7) (10,10)
Taking class intervals as: 5−9, 10−14, 15−19..., for both X and Y, construct a Bivariate Frequency Distribution.
solve  
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