RD Sharma (2019, 2020) - GeniusJnr

RD Sharma (2019, 2020) : MCQ, free quiz, mock quiz, practise questions, olympiad preparation

RD Sharma (2019, 2020)

Chapters

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Rational Numbers

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Powers

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Squares and Square Roots

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Cubes and Cube Roots

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Playing with Numbers

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Algebraic Expressions and Identities

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Questions

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Square of

(\frac{- 2}{3})

is
(a)

- \frac{2}{3}

(b)

\frac{2}{3}

(c)

- \frac{4}{9}

(d)

\frac{4}{9}

solve

Cube of

\frac{- 1}{2}

is
(a)

\frac{1}{8}

(b)

\frac{1}{16}

(c)

- \frac{1}{8}

(d)

\frac{- 1}{16}

solve

Which of the following is not equal to

{(\frac{- 3}{5})}^{4} ?

(a)

\frac{(- 3)^{4}}{5^{4}}

(b)

\frac{3^{4}}{(- 5)^{4}}

(c)

- \frac{3^{4}}{5^{4}}

(d)

\frac{- 3}{5} \times \frac{- 3}{5} \times \frac{- 3}{5} \times \frac{- 3}{5}

solve

Which of the following is not reciprocal of

{(\frac{2}{3})}^{4} ?

(a)

{(\frac{3}{2})}^{4}

(b)

{(\frac{2}{3})}^{- 4}

(c)

{(\frac{3}{2})}^{- 4}

(d)

\frac{3^{4}}{2^{4}}

solve

Which of the following numbers is not equal to

\frac{- 8}{27} ?

(a)

{(\frac{2}{3})}^{- 3}

(b)

- {(\frac{2}{3})}^{3}

(c)

{(- \frac{2}{3})}^{3}

(d)

(\frac{- 2}{3}) \times (\frac{- 2}{3}) \times (\frac{- 2}{3})

solve

{(\frac{2}{3})}^{- 5}

is equal to
(a)

{(\frac{- 2}{3})}^{5}

(b)

{(\frac{3}{2})}^{5}

(c)

\frac{2 x - 5}{3}

(d)

\frac{2}{3 \times 5}

solve

{(\frac{- 1}{2})}^{5} \times {(\frac{- 1}{2})}^{3}

is equal to
(a)

{(\frac{- 1}{2})}^{8}

(b)

- {(\frac{1}{2})}^{8}

(c)

{(\frac{1}{4})}^{8}

(d)

{(- \frac{1}{2})}^{15}

solve

{(\frac{- 1}{5})}^{3} \div {(\frac{- 1}{5})}^{8}

is equal to
(a)

{(- \frac{1}{5})}^{5}

(b)

{(- \frac{1}{5})}^{11}

(c)

(- 5)^{5}

(d)

{(\frac{1}{5})}^{5}

solve

{(\frac{- 2}{5})}^{7} \div {(\frac{- 2}{5})}^{5}

is equal to
(a)

\frac{4}{25}

(b)

\frac{- 4}{25}

(c)

{(\frac{- 2}{5})}^{12}

(d)

\frac{25}{4}

solve

{\{{(\frac{1}{3})}^{2}\}}^{4}

is equal to
(a)

{(\frac{1}{3})}^{6}

(b)

{(\frac{1}{3})}^{8}

(c)

{(\frac{1}{3})}^{24}

(d)

{(\frac{1}{3})}^{16}

solve

{(\frac{1}{5})}^{0}

is equal to
(a) 0
(b)

\frac{1}{5}

(c) 1
(d) 5

solve

{(\frac{- 3}{2})}^{- 1}

is equal to
(a)

\frac{2}{3}

(b)

- \frac{2}{3}

(c)

\frac{3}{2}

(d) none of these

solve

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