Genius Jnr - The outer shell of two eggs is removed and kept in dilute HCl. Then, one shell is placed in distilled water, while the other is placed in a saturated solution of NaCl. What will be observed?

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The outer shell of two eggs is removed and kept in dilute HCl. Then, one shell is placed in distilled water, while the other is placed in a saturated solution of NaCl. What will be observed?

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Vapour Pressure Pure Water 298 K 23 51 Mm Hg Kf Water 1 86 Degree Per Molal Got Sample Non Vola Scientist Got Non Electrolytic Compound Certain Weight Molar Mass Compound 200 Dissolved Compound Co Scientist Asked Calculate Density Ethylene Glycol Determination Freezing Point Took 50cc Ethylene Gl Student Asked Determine Molar Mass Unknown Solid Took Accurately Weighed 2 8g Solid Dissolved 100g B Saheli Got 10 G Non Volatile Solute Dissolved 100 G Water Initial Vapour Pressure 17 3555 Mm Final V Chemist Prepare Solution Percentage Weight Percentage Sodium Thiosulphate W W Prepared Percentage Mole Sodium Thiosulphate Present Solution Know Specific Gravity Water 1 Basis Molalities Na S2o32 Ions Solution Chemist Took 100g Sample Reactor Determined Percentage Mass Glucose Weight Expected Result Mass Percentage Got 100g Sample Calculated Molality Solution Percentage Mole Solution Explain Amphoteric Behaviour Amino Acids Enzymes Nucleic Acids Mention Two Important Functions Adsorption Always Exothermic Using Property Determinants Without Expanding Prove Gaseous Mixture Contains Oxygen Nitrogen Ratio 1 4 Mass Therefore Ratio Number Molecules Copper Extracted Hydrometallurgy Zinc Explain Mention Conditions Required Maximise Yield Ammonia Consider Two Isotonic Solutions Temperatures Solute Solution Molecular Mass Solute Solution B Molecu Define Following Terms Give One Example Commensalism B Parasitism C Camouflage Mutualism E Interspec Help Suitable Diagram Describe Logistic Population Growth Curve Find Second Order Derivatives Function Find Second Order Derivatives Function Henry Law Constant Solubility N2 Gas Water 298k 1 0 105 Atm Mole Fraction N2 Air 0 8 Number Moles N2 Parallel Plate Capacitor Fig 8 7 Made Circular Plates Radius R 6 0 Cm Capacitance C 100 Pf Capacitor Card Sheet Divided Squares Size 1 Mm2 Viewed Distance 9 Cm Magnifying Glass Converging Lens Focal Le Line Mx 1 Tangent Curve Y2 4x Value 1 B 2 C 3 Normal Curve X2 4y Passing 1 2 X 3 B X 3 C X 1 X 1 Double Slit Experiment Angular Width Fringe Found 0 2 Screen Placed 1 Away Wavelength Light Used 600 Draw List Democratic Rights Enjoy Today Whose Origins Could Traced French Revolution Social Differences Create Possibilities Deep Social Divisions Tensions Social Differences Usually L Difference Pressure Group Political Party Match List Organisations Struggles List Ii Select Correct Answer Using Codes Given Lists List List I 0 003 Kg Acetic Acid Added 500 Cm3 Water Depression Freezing Point 23 Acetic Acid Dissociated Given Vapour Pressure 5 Aqueous Solution Non Volatile Substance X 315 K 755 Torr Molar Mass Solute Vapour 22 1947 Write Essay Based Examples Show Conflicts Get Resolved Explain Concept Production Function Equal Volumes Ethylene Glycol Water Mixed Freezing Point Constant Water 1 86 Specific Gravity Ethyle Freezing Point Aqueous Solution Containing 5 Glucose Mass 10 Urea Mass Molal Depression Constant Wat 0 200 G Haemoglobin 20 Ml Solution 25 C Osmotic Pressure 2 88 Torr Molecular Weight Haemoglobin Freezing Point Aqueous Solution Containing 5 Glucose Mass 10 Urea Mass Molal Depression Constant Wat Density Liquid Mercury Is13 6 G Ml Many Moles 1 L Metal 50 Ml Centimolar Kmno4 Solution Sufficient Oxidise 75 Ml H2o2 Solution Presence Sulphuric Acid Follo 0 003 Kg Acetic Acid Added 500 Cm3 Water Depression Freezing Point 23 Acetic Acid Dissociated Given Mole Percent Oxygen Gaseous Mixture Containing 14 0 G Nitrogen 32 G Oxygen Freezing Point Solution Containing 0 3 G Acetic Acid 30 0 G Benzene Lowered 0 45 K Calculate Value V 0 2 Aqueous Solution Substance Boiled 100 042 C Molal Elevation Constant Water Molality 20 Mass Mass Aqueous Ki Solution Given Molar Mass Ki 166 G Mol 1 Mohit Glass Ltd Issued 20 000 Shares Rs 100 Rs 110 Per Share Payable Rs 30 Application Rs 40 Allotme 10 Cc Liquid X Mixed 10 Cc Liquid Volume Resulting Solution Found 19 8 Cc Following Statements Corre 6 023 1020 Molecules Urea Present 100 Ml Solution Concentration Solution 20 G Naphthoic Acid C11h8o2 Dissolved 50 G Benzene Kf 1 72 K Kg Mol 1 Freezing Point Depression 2 K 10 Cc Liquid X Mixed 10 Cc Liquid Volume Resulting Solution Found 19 8 Cc Following Statements Corre Explain Detail Significance Financial Statements Prepare Format Statement Profit Loss Explain Items Following Meaning Listed Dictionary Phrase Take Meaning Used Third Paragraph Account Take Sth Begin Distinguish Information Gathering Insight Formation 10 G Solute Dissolved 420 Cm3 Water Osmotic Pressure Solution Recorded 7 5 Atm 300 K Boiling Point S 0 4 Ml Butanoic Acid Density 1 06 G Ml Dissolved 660 Ml Water Depression Freezing Point Observed Aci Dissolution 15 84 G Biphenyl 115 G Benzene Boiling Point Solvent Rises 80 1 C 82 75 C Latent Heat Va 10 Wt Vol Sugar Solution Isotonic 0 087 Wt Vol Nacl Solution 298k Degree Ionization Nacl Two Solutions B Prepared Dissolving 1 6 G Acetic Acid 100 G Acetone Benzene Respectively Boiling Poi Differentiate Molarity Molality Solution Change Temperature Influence Values B Calculate Freezing P State Following Henry Law Partial Pressure Gas Mixture Ii Raoult Law General Form Reference Solutio 29 2 W W Hcl Stock Solution Density 1 25 G Ml 1 Molecular Weight Hcl 36 5 G Mol 1 Volume Ml Stock So 25 Ml Household Bleach Solution Mixed 30 Ml 0 50 Ki 10 Ml 4n Acetic Acid Titration Liberated Iodine Two Solutions B Osmotic Pressure X Atm X 8 5 Atm Weight Volume B Isotonic Pressure Molar Mass Solute Use Following Information Answer Next Question Solubility Various Substances Increases Increase Temp Conducting Absorption Spectroscopy Lake Water Found 8 Nacl 95 Ionized 11 Caso4 73 Ionized 13 5 Caco3 228 G Glucose Dissolved 100 G Water 30 C 20 G Urea Dissolved 100 G Water 15 C Ratio Osmotic Pressure 6 G Solute X 11 33 G Solute Non Electrolyte Dissolved 100 G Water Separately Tb X 1 8 C 3 1 C Differ Use Following Information Answer Next Question Soda Bottle Opened Carbon Dioxide Gas Dissolved Fizze Use Following Information Answer Next Question Water Partial Pressure Gases P Q R 5 Pa 10 Pa 15 Pa 2 Magnesium Chloride 60 Dissociated Dilute Aqueous Solution Made Dissolving 72 6 G Salt 100 G Water 10 Enthalpy Vapourisation Water 9 72 Kcal Mol 1 Boiling Point 373 15 K Boiling Point 0 50 Molal Sugar S 12 2 G Benzoic Acid C6h5cooh Added 100 G Water Ka 1 6 10 3 Kf 1 86 K Kg Mol 1 Depression Freezing Po Density 3m Solution Nacl 1 25 G Ml 1 Solution Boiled 100 042 C Molal Elevation Constant Water 0 200 G Haemoglobin 20 Ml Solution 25oc Osmotic Pressure 2 88 Torr Molecular Weight Haemoglobin Boiling Point Solution Contains 0 5 G Benzoic Acid 40 G Benzene 80 Acid Exists Dimer Benzene Given B Use Following Information Answer Next Questions Given Figure Represents Energy Diagram Reaction X Gi 20 G Naphthoic Acid C11h8o2 Dissolved 50 G Benzene Kf 1 72 K Kg Mol 1 Freezing Point Depression 2 K Vapour Pressure Component Mm 64 G Mol Component B Mm 76 G Mol 70 C 6 9 104 Nm 2 9 6 104 Nm 2 Respect Two Liquids B Osmotic Pressure X Atm X 8 5 Atm Weight Volume B Isotonic Pressure Molar Mass Solute B Use Following Information Answer Next Question Molality Solution Hcl Water 1 Density Solution 1 5 G Mass Sodium Hydroxide Naoh Required Making 4 Kg 0 5 Molal Aqueous Solution Use Following Information Answer Next Question Vapour Pressure Liquid Mixture Containing Liquids X 5 Use Following Information Answer Next Question Non Volatile Solute Molar Mass 101 2 G Mol 1 Dissolve Use Following Information Answer Next Question 25 C 30 G Urea Nh2conh2 Dissolved 720 G Water 25 C Va Use Following Information Answer Next Question 300 K 2 5 G Protein Molar Mass 102000 G Mol 1 Dissolv Use Following Information Answer Next Question Solution Prepared Dissolving Certain Amount 3 L Water Density Kcl Solution Labeled 9 W W 1 4 G Ml 1 Molarity Solution Following Statements Regarding Solubility Correct Use Following Information Answer Next Question Vapour Pressure 2 Molal Aqueous Solution Solute 11 87 Use Following Information Answer Next Question Aqueous Solution Urea Boiling Point 100 13 C Water Kf Use Following Information Answer Next Question Aqueous Solution Contains 10 Urea Weight 15 Glucose W Use Following Information Answer Next Question Osmotic Pressure Sugar Solution 2 5 105 Pa 25 C 5 Con Use Following Information Answer Next Question Vapour Pressure Pure Liquid X 0 05 Atm 300 K Vapour P Use Following Information Answer Next Question Henry Law Constant Solubility Methane Benzene 25 C 4 Use Following Information Answer Next Question Two Liquids Molar Mass 80 G Mol 1 B Molar Mass 120 G Use Following Information Answer Next Question Non Volatile Solute Molar Mass 55g Mol 1 Dissolved 11 Use Following Information Answer Next Question 1 G Organic Compound Dissolved 36 G Water Freezing Po Density 25 Mass Mass Aqueous Solution Compound Molar Mass 75 G Mol 1 1 45 G Ml 1 Molarity Following Matter Form Solution Water Salad Example Mixture Ii Composition Row Completes Given Statement Differentiate Contract Manufacturing Setting Wholly Owned Production Subsidiary Abroad Use Following Information Answer Next Question Material Containing Two Substances Known Mixture Mixt Car Travelling 20 Along Road Child Runs Road 50 Ahead Car Driver Steps Brake Pedal Must Car Decelera Name Scientist Gave Laws Motion Piece Wire 234 Metres Long Broke Two Pieces One Piece 58 Metre Long Long Piece Much 84 5 Decreased Get 27 84 Tick Correct Answer 7 26 1639 1178 B 1178 C 1139 1139 Find Area Square Plot Land Whose Side Measures 812 Metres Evaluate 625729 Evaluate 33 64 Use Following Information Answer Next Question 0 33 G Naoh Added Water Make 6 L Solution 277 K Conce Find Value Using Diagonal Method 67 2 Following Squares Odd Numbers 484 Ii 961 Iii 7396 Iv 8649 V 4225 Express Following Standard Form 345 Ii 180000 Iii 0 000003 Iv 0 000027 Tick Correct Answer 3670000 Standard Form 367 104 B 36 7 105 C 3 67 106 None Solubility Gas Decreases Particular Solution Contains Gaseous Solid Solutes Effect Increase Pressure Solubility Solutes 3 Digit Number Tens Digit Thrice Units Digit Hundreds Digit Four Times Units Digit Also Sum Digits 1 Two Digit Number Digit Units Place Double Digit Tens Place Number Exceeds Sum Digits 18 Find Number Use Following Information Answer Next Question Solutions Mixtures Two Substances Whose Distribution Use Following Information Answer Next Question Mechanical Mixture Amixture Two Substances Distributi Bag Contains 16 Cards Bearing Numbers 1 2 3 16 Respectively One Card Chosen Random Probability Chose Bag Contains 5 Red 8 Black 7 White Balls One Ball Chosen Random Probability Chosen Ball Black 23 B 2 Use Following Information Answer Next Question Homogeneous Mixture Solution One Particle Size Order Following Mixtures Example Homogeneous Mixture Existing Solid Phase Following Mixtures Example Homogeneous Mixture Metals Use Following Information Answer Next Question Mixture Said Heterogeneous Composition Uniform Throug Use Following Information Answer Next Question Solution Contains 10 G Salt 10 G Sugar One Liter Wate Cricket Match Batsman Hits Boundary 6 Times 30 Balls Plays Probability Given Delivery Ball Hit Bound Following Liquids Solution Following Substances Example Mixture Use Following Information Answer Next Question Material Containing Two Substances Known Mixture Mixt Use Following Information Answer Next Question Given Temperature Solution Cannot Dissolve Solute Hol Use Following Information Answer Next Question Homogeneous Mixture Solution One Particle Size Order Salad Example Mixture Ii Composition Row Completes Given Statement Use Following Information Answer Next Question Alloy Copper Zinc Known Alloy Carbon Iron Known Alter Use Following Information Answer Next Question Material Containing Two Substances Known Mixture Mixt Use Following Information Answer Next Question 6 G Ethanoic Acid Ch3 Cooh Dissolved 80 G Benzene C6h Use Following Information Answer Next Question 350 G 20 W W Solution Mixed 300 G 35 W W Solution Mas Following Mixtures Example Homogeneous Mixture Metals Following Mixtures Example Homogeneous Mixture Existing Solid Phase Alloys Concentration Solution B Solution Contains 80g Glucose 420 G Water Calculate Concentration Glucose Define Term Molality B Calculate Molality 20 Mass Mass Aqueous Ki Solution Molar Mass Ki 166 G Mol Define Molal Elevation Constant B 0 2 Molal Aqueous Solution Substance Boiled 100 042 C Calculate M Differentiate Osmosis Diffusion Define Molal Elevation Constant B 0 2 Molal Aqueous Solution Substan Various Factors Affect Solubility Gas Azeotropic Mixtures Give Examples Two Types Azeotropes Mixture Salt Water Homogenous Justify Statement Alloys Considered Mixtures Give One Example Following Mixtures Liquid Liquid Ii Solid Solid Iii Solid Liquid Animal Recklessly Hunted Prairies Antelope B Bison C Coyote Dingo Mention Large Scale Use Phenomenon Called Reverse Osmosis One Following Planets Inner Planet Mercury B Saturn C Mars Venus Earth Unique Planet Solar System Total Number Parallels Interval 5 37 B 36 C 19 42 Explain Following Terms 30 Words 1 Equator 2 Earth Grid 3 Heat Zones 4 Great Circle 5 Prime Meridian One Following Factors Responsible Phenomenon Seasons Rotation Earth B Revolution Earth C Earth Incli Length Daylight Equator Sun Rays Never Vertical Arctic Circle People Work Streets Self Employed Important Unit Administration Country B Pargana C District Tehsil Role Committees Play Municipalities Municipal Corporation Elected Head Municipal Corporation Known Mayor Alderman B Commissioner C Mahapaur Mahajan Representative Block Samitis District Members Work District Level Makes Panchayati Raj B Zila Parish Important Role Citizen Democracy Written Constitution Necessary Write Two Differences Parliamentary Form Presidential System Govenment Define Term Stereotype Children Special Needs Longer Called Diverse B Disabled C Prejudiced Unusual Art Folk Theatre Give Two Examples X 3x 14 Dx 17x 53 15x 4 Dx F X 8x3 2x F 2 8 Find F X Alloys Non Ideal Solutions Exhibit Either Positive Negative Deviations Raoult Law Deviations Caused Explain Solution Prepared Dissolving 1 25 G Oil Winter Green Methyl Salicylate 99 0 G Benzene Boiling Point Happen Boiling Point Solution Weight Solute Dissolved Doubled Weight Solvent Taken Reduced Half Meant 10 Aqueous Solution Sodium Carbonate Value Van Hoff Factor Unity Conditions Non Ideal Solutions Exhibit Negative Deviations Raoult Law 0 1 Molal Solutions Glucose Sodium Chloride Higher Boiling Point Mole Fraction Solute X Molal Solution Compound Benzene 0 2 Value X Happens Molarity Temperature Solution Increased Freezing Point Solution Containing 0 3 G Acetic Acid 30 0 G Benzene Lowered 0 45 K Calculate Van Hof Outer Shell Two Eggs Removed Kept Dilute Hcl One Shell Placed Distilled Water Placed Saturated Solut Name Explain Factor Introduced 1880 Account Extent Association Dissociation B Arrange Following Solu Molality Preferred Molarity Expressing Concentration Solution B Boiling Point Water Increase Sodium Raoult Law Considered Special Case Henry Law Water Carbon Tetrachloride Immiscible Water Ethanol Miscible Proportions Explain B 5 25 Solution Sub Dissolution Solid Compounds Exothermic Nature Compounds Endothermic Nature 0 1539 Molal Aqueous Solution Cane Sugar Mol Mass 342 Gmol 1 Freezing Point 271 K Freezing Point Pur Solution Concentrated 1 Molal 1 Molar Calculate Number Molecules Present 0 1 Mole N2 Gas B Mass 0 2 Molecular Weight 0 200 G Haemoglobin 20 Ml Solution 25 C Osmotic Pressure 2 88 Torr 0 1 Mole Sugar Dissolved 1 Kg Water Depression Freezing Point Found 0 186 K Conclusions Drawn Molecu Mole Fraction Ethanol Water Sample Rectified Spirit Containing 95 Percent Ethanol Weight Atomic Numb Vapour Pressure 5 Aqueous Solution Non Volatile Substance Xat 315 K 755 Torr Calculate Molar Mass So Solution Containing 0 456 G Camphor Molecular Mass 152 G Dissolved 31 4 G Acetone Boiling Point 56 3 Ph 0 01 Acetic Acid Van Hoff Factor Equal 1 04 Aqueous Solution Dibasic Acid Molecular Mass 118 G Contains 35 4 G Acid Per Litre Solution Density 1 Vapour Pressure Pure Cs2 50 C 854 Torr Vapour Pressure Solution 2 0 G Sulphur 100 G Cs2 848 9 Torr F Equal Amounts Two Solutes B Dissolved Separately 50g Solvent C Molecule Heavier Molecule B Solution 0 003 Kg Acetic Acid Added 500 Cm3 Water Calculate Depression Freezing Point 23 Acetic Acid Dissocia Give Reasons Following Statements Mixture Chlorobenzene Bromobenzene Nearly Ideal Solution Mixture C Explain Lowering Vapour Pressure Solution Non Volatile Solute Added Volatile Solvent Calculate Osmotic Pressure Decimolar Solution Potassium Ferrocyanide 50 Dissociated 300 K Liquid X 10 Cc Volume Mixed 10 Cc Liquid Volume Resulting Solution Found 19 8 Cc Concluded Given Obs Freezing Point Aqueous Solution Containing 5 Mass Glucose 10 Mass Urea Molal Depression Constant Wat Depression Freezing Point Solution Containing 50 Cm3 Ethylene Glycol 50 G Water Found 34 K Assuming Addition Hgi2 Aqueous Solution Ki Shows Increase Vapour Pressure Calculate Concentration Solution Obtained Mixing 300 G 25 Aqueous Solution Nh4no3 150 G 40 Aqueous S Derive Relationship Osmotic Pressure Molar Mass Solute Explain Raoult Law Special Case Henry Law Define Mixture Name Different Types Mixture Separate Mixture Sodium Chloride Water Liquids Lemonade Taste Throughout Following Substances Mixtures Soil Air Sugar Salt Name Solid Solution Differentiate Following Gas Vapour Ii Homogeneous Heterogeneous Materials Iii Boiling Condensation Mass Volume Percentage Solution Containing 50 G Sugar 500 Ml Water Fill Blank Mixing Gases Called Define Mixture Name Different Types Mixture Separate Mixture Sodium Chloride Water Define Solution Solvent Solute Give One Example Differentiate Molality Molarity Solution Effect Change Temperature Solution Molality Molarity 22 1 G Phosphorous Formula Px Dissolved 250 Ml Benzene Kf 5 12 Depression Freezing Point Observed 3 Solution X G Glucose Dissolved 280 G Water Lowering Vapour Pressure Observed 2 5 Mm Hg Vapour Pressu Solution 15 G Compound X Non Electrolyte Dissolved 250 G Compound Boiling Point Elevation 0 58 C Mol Van Hoff Factor Benzoic Acid Benzene 65 Association Takes Place Abnormal Molecular Weight Quaternary Electrolyte Ab3 Magnesium Chloride 60 Dissociated Dilute Aqueous Solution Made Dissolving 72 6 G Salt 100 G Water 10 Enthalpy Vapourisation Water 9 72 Kcal Mol 1 Boiling Point 373 15 K Boiling Point 0 50 Molal Sugar S 12 2 G Benzoic Acid C6h5cooh Added 100 G Water Ka 1 6 10 3 Kf 1 86 K Kg Mol 1 Depression Freezing Po Density 3m Solution Nacl 1 25 G Ml 1 Solution Boiled 100 042 C Molal Elevation Constant Water 0 200 G Haemoglobin 20 Ml Solution 25oc Osmotic Pressure 2 88 Torr Molecular Weight Haemoglobin 50 G Copper Sulphate 100 Ml Water 80 Ml Alcohol 40 Ml Water Substances Dissolved Liquid Recovered Two Ways Evaporation Crystallisation Two Techniques One Better Solvent Present Tincture Iodine Terms Solute Solvent Used Describing Kind Mixture Following Statement True 7 5 B 7 5 C 7 5 0 7 5 0 5 Less 2 3 B 3 C 7 7 6 7 1 B 1 C 13 13 Use Following Information Answer Next Question Component Solution Dissolves Component Called Compone Use Following Information Answer Next Question Sodium Chloride Water Example Mixture Particlesa Beam 184 Term Ap 3 7 11 15 Following Mixtures Particle Size Solute 0 1 Nm 1 Nm Write Two Differences Homogenous Heterogeneous Mixtures Give Example Write Three Properties True Solution B Sugar Solution Contains 40 G Sugar 60 G Water Concentration Properties True Solution B Solution Contains 40 G Sugar 60 G Water Express Concentration Terms Mass Mean Saturated Unsaturated Solution Effect Temperature Solubility Substance Solvent Student Finds Writing Blackboard Blurred Unclear Sitting Last Desk Classroom However Sees Clearly Si Solution Tincture Iodine Solvent Involuntary Actions Body Controlled Medulla Fore Brain B Medulla Mid Brain C Medulla Hind Brain Medu Volume 1 25 Hcl Required Completely Neutralize 17 3 Ml 0 5 Naoh Use Following Information Answer Next Question Solutions Mixtures Two Substances Whose Distribution Use Following Information Answer Next Question Mechanical Mixture Amixture Two Substances Distributi Use Following Information Answer Next Question Homogeneous Mixture Solution One Particle Size Order Following Mixtures Example Homogeneous Mixture Existing Solid Phase Sugar Dissolved Water Hence Sugar Use Following Information Answer Next Question Solution Contains 10 G Salt 10 G Sugar One Liter Wate Following Liquids Solution Use Following Information Answer Next Question Substance Dissolved Liquid Substance Gets Dissolved C Choose Statement False Regarding Solutes Solvents Solutions Use Following Information Answer Next Question Solution Made Mixing 20 Ml Honey 50 Ml Milk 15 Ml Sug Use Following Information Answer Next Question Air Mixture Nitrogen Oxygen Argon Carbon Dioxide Heli Factor Affect Solubility Solute Use Following Information Answer Next Question Addition Table Salt Affects Boiling Temperature Water Salad Example Mixture Ii Composition Option Completes Given Statement Following Mixtures Example Solution Mass Sodium Hydroxide Naoh Required Making 4 Kg 0 5 Molal Aqueous Solution Use Following Information Answer Next Question Non Volatile Solute Molar Mass 101 2 G Mol 1 Dissolve Use Following Information Answer Next Question 300 K 2 5 G Protein Molar Mass 102000 G Mol 1 Dissolv Use Following Information Answer Next Question Solution Prepared Dissolving Certain Amount 3 L Water Use Following Information Answer Next Question 350 G 20 W W Solution Mixed 300 G 35 W W Solution Mas Following Statements Regarding Solubility Correct Use Following Information Answer Next Question Vapour Pressure 2 Molal Aqueous Solution Solute 11 87 Use Following Information Answer Next Question Aqueous Solution Urea Boiling Point 100 13 C Water Kf Use Following Information Answer Next Question Aqueous Solution Contains 10 Urea Weight 15 Glucose W 25 C Osmotic Pressure Sugar Solution 2 5 105 Pa Concentration Given Sugar Solution Use Following Information Answer Next Question Vapour Pressure Pure Liquid X 0 05 Atm 300 K Vapour P Use Following Information Answer Next Question Henry Law Constant Solubility Methane Benzene 25 C 4 Use Following Information Answer Next Question Two Liquids Molar Mass 80 G Mol 1 B Molar Mass 120 G Use Following Information Answer Next Question Non Volatile Solute Molar Mass 55g Mol 1 Dissolved 11 Use Following Information Answer Next Question 1 G Organic Compound Dissolved 36 G Water Freezing Po Person Suffering High Blood Pressure Advised Take Less Quantity Common Salt Equal Amounts Two Solutes B Dissolved Separately 50g Solvent C Molecule Heavier Molecule B Solution Happens Vapour Pressure Water Table Salt Added Lowering Vapour Pressure Colligative Property Liquid X 10 Cc Volume Mixed 10 Cc Liquid Volume Resulting Solution Found 19 8 Cc Concluded Given Obs Addition Hgi2 Aqueous Solution Ki Shows Increase Vapour Pressure Effect Temperature Osmotic Pressure Solution Effect Increase Temperature Solubility Gas Liquid Outer Shells Removed Two Eggs One Eggs Placed Pure Water Placed Saturated Solution Nacl Observed Freezing Point Sucrose Solution Prepared Dissolving 34 2 G 1000 G Water 273 K Kffor Water 1 86 K Kg Write Expression Calculation Molar Mass Unknown Non Volatile Compound Elevation Boiling Point Meant Azeotrope Sketch Graph Showing Negative Deviation Raoult Law Salts Nacl Cacl2 Scattered Icy Roads Higher Altitudes Scuba Divers Suffer Bends Rise Surface Abruptly Sketch Vapour Pressure Temperature Graph Showing Elevation Boiling Point 0 1 Mole Sugar Dissolved 1 Kg Water Depression Freezing Point Found 0 186 K Conclusions Drawn Molecu Vapour Pressure 5 Aqueous Solution Non Volatile Substance Xat 315 K 755 Torr Calculate Molar Mass So Ph 0 01m Acetic Acid Van Hoff Factor Equal 1 14 Colligative Property Preferred Determination Molar Mass Polymers Give Reasons 0 003 Kg Acetic Acid Added 500 Cm3 Water Calculate Depression Freezing Point 23 Acetic Acid Dissocia Derive Relationship Osmotic Pressure Molar Mass Solute Freezing Point Aqueous Solution Containing 5 Mass Glucose 10 Mass Urea Molal Depression Constant Wat Explain Lowering Vapour Pressure Solution Non Volatile Solute Added Volatile Solvent Explain Raoult Law Special Case Henry Law Explain Example Minimum Maximum Boiling Azeotrope Molecular Weight 0 200 G Haemoglobin 20 Ml Solution 25 C Osmotic Pressure 2 88 Torr Solution Containing 0 456 G Camphor Molecular Mass 152 G Dissolved 31 4 G Acetone Boiling Point 56 3 Vapour Pressure Pure Cs2 50 C 854 Torr Vapour Pressure Solution 2 0 G Sulphur 100 G Cs2 848 9 Torr F Explain Dried Fruits Vegetables Placed Water Slowly Swell Return Original Form Effect Increase Tempe Mixture Chlorobenzene Bromobenzene Nearly Ideal Solution Mixture Chloroform Acetone Temperature 0 5 Solution Sodium Chloride Shows Higher Value Osmotic Pressure 0 5 Glucose Solution Calculate Osmotic Pressure Decimolar Solution Potassium Ferrocyanide 50 Dissociated 300 K Explain Dissolution Solid Compounds Exothermic Others Endothermic Water Cannot Separated Completely Ethyl Alcohol Fractional Distillation Conditions Van Hoff Factor Equal 1 Amount Sodium Chloride Must Added 1 Kg Water Freezing Point Solution Lowered 3 K Kf Water 1 86 K Kg Molality Solution Boiling Point Solution Lowering Vapour Pressure 298 K Given Kf 1 86 K Kg Mol 1 Kb 0 512 K Kg Mol 1 Vapour Pressure Water 29 Molecular Mass Insulin Osmotic Pressure Solution Containing 20 Mg Insulin 10 Cm3 6 48 Torr 25 C Happen Boiling Point Solution Weight Solute Dissolved Doubled Weight Solvent Taken Reduced Half Value Van Hoff Factor Unity Conditions Non Ideal Solutions Exhibit Negative Deviations Raoult Law 0 1 Molal Solutions Glucose Sodium Chloride Higher Boiling Point Value Van Hoff Factor Compound Undergoes Dimerization Organic Solvent Pressure Cooker Reduce Cooking Time Raoult Law Considered Special Case Henry Law Dissolution Solid Compounds Exothermic Nature Compounds Endothermic Nature Depression Freezing Point Solution Containing 50 Cm3 Ethylene Glycol 50 G Water Found 34 K Assuming Freezing Point Solution Containing 0 3 G Acetic Acid 30 0 G Benzene Lowered 0 45 K Calculate Van Hof Outer Shell Two Eggs Removed Kept Dilute Hcl One Shell Placed Distilled Water Placed Saturated Solut Explain Bottle Containing Liquid Ammonia Kept Ice Opened Water Carbon Tetrachloride Immiscible Water Ethanol Miscible Proportions Explain 5 25 Solution Substance Isotonic 1 5 Solution Urea Molecular Mass 60 G Mol 1 Solvent Molar Mass Subs 0 1539 Molal Aqueous Solution Cane Sugar Mol Mass 342 Gmol 1 Freezing Point 271 K Freezing Point Pur Happens Pressure Greater Osmotic Pressure Applied Solution Separated Solvent Semi Permeable Membrane Use Process Carried Plant Net Flow Solvent Take Place Name One Semi Permeable Membrane Used Plant Plot Graph Vapour Pressure Temperature Show Depression Freezing Point Along Decrease Vapour Pressure Write Expression Molal Depression Constant Terms Enthalpy Fusion Name Explain Factor Introduced 1880 Account Extent Association Dissociation Arrange Following Solutions Increasing Order Osmotic Pressure Give Reasons Answer 34 2 G L Sucrose I Boiling Point Water Increase Sodium Chloride Added Use Following Information Answer Next Question Ammonium Nitrate Contains 33 Per Cent Nitrogen Calciu Volume Water Added 350 Ml 0 33 Sugar Solution Order Make 0 15 Sugar Solution Use Following Information Answer Next Question Graph Shows Solubility Curves Potassium Nitrate Sodiu Use Following Information Answer Next Question Graph Shows Solubility Curves Potassium Nitrate Sodiu Use Following Information Answer Next Question Solubility Various Substances Increases Increase Temp Use Following Information Answer Next Question 2 L Solution Prepared Dissolving 0 4 G Nacl Water 277 Solubility Gas Decreases Solubility Solute Depends Particular Solution Contains Gaseous Solid Solutes Effect Increase Pressure Solubility Solutes Following Factors Affect Solubility Solid Liquid Solutes Solvent Following Factors Affect Rate Dissolution Solid Liquid Solutes Solvent Use Following Information Answer Next Question Solubility Organic Compound Increases Increase Branch Use Following Information Answer Next Question Water Partial Pressure Gases P Q R 5 Pa 10 Pa 15 Pa 2 Use Following Information Answer Next Question Soda Bottle Opened Carbon Dioxide Gas Dissolved Fizze Lowering Vapour Pressure Equal Freezing Point Solution Mixing Non Volatile Solute Solvent Vapour Pressure Decreases 0 9 Atm 0 55 Atm Total Number Moles Sol Principle Behind Separation Technique Used Separate Sand Gravel Explain Process Separate Ammonium Chloride Salt Explain Process Obtain Salt Salt Solution Separate Mixture Containing Sand Salt Complete Given Table Mixture Separation Technique Sugar Solution Sand Containing Pebbles Fruit Juice Technique Used Separate Insoluble Solid Liquid Using Porous Material Technique Commonly Used Homes Separate Husk Flour Separation Technique Employed Obtain Salt Sea Water Following Water Bodies Source Fresh Water Earth Correct Order Increasing Solubility N Octane Nacl Ch3oh Benzene Following Solutions Ideal Nature Components Following Mixtures Immiscible Understand Term Mixture Give One Example Following Gaseous Heterogeneous Mixture B Solid Homogeneous Mixture Complete Following Table Mixture Example Liquid Homogeneous Mixture Solid Heterogeneous Mixture Gas Following Substances Example Mixture Following Statements Incorrect Following Statements Compounds Incorrect Difference Homogeneous Heterogeneous Mixtures Following Substances Example Homogeneous Mixture Following Match Ups Incorrect Following Mixtures Heterogeneous Use Following Information Answer Question Rakesh Finds Bottle Containing Clear Liquid Chemistry Lab Concentrated Sulphuric Acid Peddled Commercially 95 H2so4 Weight Density Commercial Acid 1 834 G Cm Solution Containing 0 85g Zncl2 125 0 G Water Freezes 0 23 C Apparent Degree Dissociation Salt Kf Wa Mole Fraction Solute One Molal Aqueous Solution 1 2 5 Litre Naoh Solution Mixed Another 0 5 3 Litre Naoh Solution Find Molarity Resultant Solution Molarity Liquid Hcl Density Solution 1 17 G Cc 15 Ppm Ccl4 Mass Equal Molality Nacl Solution Prepared Mixing 10 G Nacl 200 G H2o Mole Fraction Percentage W W Hcl 5m Hcl Solution Mole Fraction Hcl 20 Aqueous Solution Mass Freezing Point 1 00 Aqueous Solution Hf Found 1 91 C Freezing Point Constant Water Kf 1 86 K Kg Mol State Raoult Law Solution Containing Volatile Components Raoult Law Become Special Case Henry Law B 18 G Glucose C6h12o6 Molar Mass 180 G Mol 1 Dissolved 1 Kg Water Sauce Pan Temperature Solution Boil Determine Osmotic Pressure Solution Prepared Dissolving 2 5 10 2 G K2so4 2l Water 25 C Assuming Comp 18 G Glucose C6h12o6 Molar Mass 180 G Mol 1 Dissolved 1 Kg Water Sauce Pan Temperature Solution Boil Determine Osmotic Pressure Solution Prepared Dissolving 2 5 10 2 G K2so4 2l Water 25 C Assuming Comp 18 G Glucose C6h12o6 Molar Mass 180 G Mol 1 Dissolved 1 Kg Water Sauce Pan Temperature Solution Boil Determine Osmotic Pressure Solution Prepared Dissolving 2 5 10 2 G K2so4 2l Water 25 C Assuming Comp 1 00 Molal Aqueous Solution Trichloroacetic Acid Ccl3cooh Heated Boiling Point Solution Boiling Poin Calculate Amount Kcl Must Added 1 Kg Water Freezing Point Depressed 2k Kf Water 1 86 K Kg Mol 1 1 00 Molal Aqueous Solution Trichloroacetic Acid Ccl3cooh Heated Boiling Point Solution Boiling Poin Solution Glycerol C3h8o3 Water Prepared Dissolving Glycerol 500 G Water Solution Boiling Point 100 4 1 00 Molal Aqueous Solution Trichloroacetic Acid Ccl3cooh Heated Boiling Point Solution Boiling Poin 15 0 G Unknown Molecular Material Dissolved 450 G Water Resulting Solution Found Freeze 0 34 C Molar Liquids Mixing Form Azeotropes Azeotropes State Henry Law Effect Temperature Solubility Gas Liquid Calculate Mass Compound Molar Mass 256 G Mol 1 Dissolved 75 G Benzene Lower Freezing Point 0 48 K Kf Isotonic Solutions Calculate Mass Compound Molar Mass 256 G Mol 1 Dissolved 75 G Benzene Lower Freezing Point 0 48 K Kf Define Ideal Solution Write One Characteristics Type Intermolecular Attractive Interaction Exists Pair Methanol Acetone State Raoult Law Solution Containing Volatile Components Similarity Raoult Law Henry Law Calculate Mass Compound Molar Mass 256 G Mol 1 Dissolved 75 G Benzene Lower Freezing Point 0 48 K Kf Define Following Terms Molarity Ii Molal Elevation Constant Kb B Solution Containing 15 G Urea Mola Define Following Terms Molarity Ii Molal Elevation Constant Kb B Solution Containing 15 G Urea Mola Meant Positive Deviations Raoult Law Give Example Sign Mixh Positive Deviation Define Azeotropes Typ 3 9 G Benzoic Acid Dissolved 49 G Benzene Shows Depression Freezing Point 1 62 K Calculate Van Hoff Meant Positive Deviations Raoult Law Give Example Sign Mixh Positive Deviation Define Azeotropes Typ Following Reactions Occur Cathode Electrolysis Aqueous Silver Chloride Solution Ag Aq E Ags E 0 80 3 9 G Benzoic Acid Dissolved 49 G Benzene Shows Depression Freezing Point 1 62 K Calculate Van Hoff Meant Positive Deviations Raoult Law Give Example Sign Mixh Positive Deviation Define Azeotropes Typ Following Reactions Occur Cathode Electrolysis Aqueous Silver Chloride Solution Ag Aq E Ags E 0 80 3 9 G Benzoic Acid Dissolved 49 G Benzene Shows Depression Freezing Point 1 62 K Calculate Van Hoff Solution Containing Non Volatile Solute Higher Boiling Point Pure Solvent Elevation Boiling Point Co Calculate Freezing Point Solution 31 G Ethylene Glycol C2h6o2 Dissolved 500 G Water Kf Water 1 86 K Meant Negative Deviation Raoult Law Give Example Sign Mixh Negative Deviation Define Azeotropes Type Calculate Mass Nacl Molar Mass 58 5 G Mol 1 Dissolved 37 2 G Water Lower Freezing Point 2 C Assuming Calculate Freezing Point Solution 1 9 G Mgcl2 95 G Mol 1 Dissolved 50 G Water Assuming Mgcl2 Underg Gas Soluble Water Gas B Temperature One Two Gases Higher Value Kh Henry Constant Ii Non Ideal Solut Calculate Boiling Point Solution 4 G Mgso4 120 G Mol 1 Dissolved 100 G Water Assuming Mgso4 Undergoe Define Following Terms Colligative Properties Ii Molality 10 Solution Mass Sucrose Water Freezing Point 269 15 K Calculate Freezing Point 10 Glucose Water Fre Define Following Terms Ideal Solution Ii Molarity Define Following Terms Abnormal Molar Mass Ii Van Hoff Factor 10 Solution Mass Sucrose Water Freezing Point 269 15 K Calculate Freezing Point 10 Glucose Water Fr Calculate Freezing Point Solution Containing 60 G Glucose Molar Mass 180 G Mol 1 250 G Water Kf Wate Give Reasons Following Measurement Osmotic Pressure Method Preferred Determination Molar Masses Macr Sample Water Taken Pond Found Boiling Point Sample X C 1 Atm Pressure Choose Correct Option Justify Use Following Information Answer Next Question Osmosis Particles Move Body Lower Concentration Highe State Raoult Law Solution Containing Volatile Components Write Two Characteristics Solution Obeys Ra 4 Solution W W Sucrose 342 G Mol 1 Water Freezing Point 271 15 K Calculate Freezing Point 5 Glucose Write Two Differences Ideal Solution Non Ideal Solution State Henry Law Write Two Applications Following Example Solution Solder Ii Air Iii Brass Iv Tincture Iodine Star Badminton Player P V Sindhu India Recently Bronze Medal Outstanding Performance Chemistry Stude 91 G Solvent Room Temperature 25 C 13 G Solute X Dissolved Calculate Solubility X Mentioned Temperat Explain Effect Temperature Pressure Solubility Solids Liquids Ii Gases Liquids Name State Solvent Copper Dissolved Gold According Law Total Pressure Solution Phase Container Sum Partial Pressures Components Solution Assertion Non Ideal Solution Shows Positive Negative Deviation Raoult Law Reason Solute Solvent Inte Assertion Molarity Solution Liquid State Changes Temperature Reason Volume Solution Changes Change T Assertion Adding Nacl Water Vapour Pressure Increases Reason Addition Non Volatile Solute Increases Assertion Molality Regarded Better Criterion Measurement Concentration Reason Molality Independent T Dissolution Sugar Water Explained Interactions Law Explained Mathematical Relation P Khxb Value Kh N2 Gas Water 298 K 86 76 Kbar Value Kh N2 Water 303 K Kbar Name Colourless Gas Evolved Lot Effervescence Pinch Salt Nacl Added Freshly Opened Bottle Coca Cola Solubility Kcl Water Increases Rise Temperature Dissh Kcl Water Write Role Dilute Nacn Extraction Gold B Co Extraction Iron Assertion 0 1 Solution Kcl Greater Osmotic Pressure 0 1 Solution Glucose Temperature Reason R Soluti State Raoult Law Solution Containing Volatile Components Similarity Raoult Law Henry Law 0 01 Aqueous Solution Alcl3 Freezes 0 068 C Calculate Percentage Dissociation Given Kf Water 1 86 K Assertion Elevation Boiling Point Colligative Property Reason R Elevation Boiling Point Directly Pro Tincture Iodine Prepared Dissolving Smallest Unit Compound Assertion Nacl Added Water Depression Freezing Point Observed Reason Lowering Vapour Pressure Soluti Concentration Dissolved Oxygen 50 C Pressure One Atmosphere Partial Pressure Oxygen 50 C 0 14 Atm He Derive Mathematical Expression Molar Mass Non Volatile Solute Elevation Boiling Point State Explain Derive Van Hoff General Solution Equation Define Following Terms Isotonic Solution Ii Hypertonic Solution Iii Hypotonic Solution Following 0 1 Aqueous Solutions Exert Highest Osmotic Pressure Al2 So4 3 B Na2so4 C Mgcl2 Kcl Answer Six Following Derive Relation Elevation Boiling Point Molar Mass Solute Derive Relationship Relative Lowering Vapour Pressure Molar Mass Solute Answer One Following State Faraday First Law Electrolysis Write Two Uses Following H2so4 B Chlorine Define Boiling Point Write Formula Determine Molar Mass Solute Using Freezing Point Depression Metho Vapour Pressure Pure Benzene 640 Mm Hg 2 175 10 3 Kg Non Volatile Solute Added 39 G Benzene Vapour P Determination Molar Mass Elevation Boiling Point Called Cryoscopy B Colorimetry C Ebullioscopy Spect Molarity 15 W V Solution Glucose Mol Mass 180 Increase Temperature Value Henry Constant Solution Containing Two Liquids 1 2 Vapour Pressures Pure Form P1o P2o X2 Represents Mole Fraction L Following Question Statement Assertion Followed Statement Reason Choose Correct Answer Following Cho Osmosis Solvent Molecules Move Solution 10 G Non Volatile Solute Dissolved 100 G Benzene Boiling Point Raised 1oc Calculate Molar Mass Solut Vapour Pressure Pure Benzene 620 Mm Hg 0 4 G Non Volatile Solute Molar Mass 64 G Mol 1 Dissolved 80 One Following Mixtures Example Homogeneous Mixture Would Molality Resulting Acetic Acid Solution Van Hoff Factor Case Calculate Dissociation Constant Acetic Acid Statement True Solubility Sodium Sulphate